Sorry i am a clumsy one

Algebra Level 2

There are two silos which are the same. If $a$ , $b$ and $c$ wants to take away all the resources from the silos, $a$ will need 6 hours, $b$ will need 7 hours and $c$ will need 14 hours. $a$ and $b$ starts to take the resources at the same time. When starting, $c$ helped $a$ for some time and then help $b$ afterwards. When they finished taking away the resources, they both finished at the same time. Ask how long did $c$ helped $a$ and $b$ ?

Ps. I made a mistake once again! Sorry I was clumsy this month for some reason.

C helped A 2.8 hours, B 4.8 hours C helped A 1.75 hours, B 3.5 hours C helped A 2 hours, B 3 hours C helped A 4 hours, B 2.5 hours

1 solution

Interliser 727
Jul 24, 2018

So assume that if three of them work together, they will get a efficiency of $\frac{1}{6}$ + $\frac{1}{7}$ + $\frac{1}{14}$ = $\frac{8}{21}$

But there's a tricky part. There is 2 job at the same time. So we get $\frac{2}{1}$ divided by $\frac{8}{21}$ = $\frac{21}{4}$

Therefore, we can find the time $c$ helped $a$ ,

$(1-\frac{1}{6}$ $\times$ $\frac{21}{4}$ ) divided by $\frac{1}{14}$ =1.75 hours. Thus, we can find $b$ as $\frac{21}{7}$ - $\frac{7}{4}$ =3.5 hours.

Sorry i am a clumsy one

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