Special Relativity: Relativistic Mass

In a joint Hungarian-German study, a solidified ice block of Hydrogen ( H 1 1 H^1_1 ) was accelerated to 0.75 c 0.75c , where c c is the speed of light in vacuum. Determine the observable relativistic mass ( M M ) of the H 1 1 H^1_1 block when the rest mass ( m m_{\circ} ) is 92 kg 92 \text{ kg } by using the following formula:

M = γ m = m 1 v 2 c 2 M = \gamma m_{\circ} = \frac{m_{\circ}}{ \sqrt{1 - \frac{v^2}{c^2}}}


David's Special Relativity Set
139 kg 140 kg 141 kg 142 kg Correct M M not listed

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1 solution

David Hontz
Dec 22, 2016

M = γ m = m 1 v 2 c 2 = 92 1 ( 0.75 c ) 2 c 2 = 92 1 0.5625 c 2 c 2 = 92 1 0.5625 = 92 0.4375 = 139 kg M = \gamma m_{\circ} = \frac{m_{\circ}}{ \sqrt{1 - \frac{v^2}{c^2}}} = \frac{92}{ \sqrt{1 - \frac{(0.75c)^2}{c^2}}} = \frac{92}{ \sqrt{1 - \frac{0.5625c^2}{c^2}}} = \frac{92}{ \sqrt{1 - 0.5625}} = \frac{92}{ \sqrt{0.4375}} = \boxed{139 \text{ kg}}

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