$\large Method1$

We choose the ground as system $S$ ,the heaven as system $S'$ .Suppose there are two events A and B in $S'$ and their coordinates are $A(x_{1}'\,0,0,t_{1}'$ )and $B(x_{2}'\,0,0,t_{2}'$ ) （t1' and t2' are the moment A and B happen）.Considering that displacement and time influence each other in special relativity , we must choose the same place in order to ensure the accuracy of the measurement,as a result of which we should ensure $x_{1}'\ =x_{2}'$ .Suppose that $t_{1}and t_{2}$ are the moment people in $S$ see A and B happen.Suppose velocity of the heaven is u .

Accroding to Lorentz transformation :

$\begin{aligned}t &=\frac{t'+\frac{u}{c^{2}}x'}{\sqrt{1-\frac{u^{2}}{c^{2}}}} \end{aligned}$

So $\begin{aligned} t2-t1&=\frac{t2'-t1'+\frac{u}{c^{2}}(x2'-x1')}{\sqrt{1-\frac{u^{2}}{c^{2}}}} \\&=\frac{t2'-t1'}{\sqrt{1-\frac{u^{2}}{c^{2}}}} \\& Know: t2-t1=365days，t2'-t1'=1day\end{aligned}$

Just put in the statistics ,we can easily get the answer is $\boxed{u=0.999996c}$

$\begin{aligned} \large Method2\ \end{aligned}$

use time dilation effect directly

$Δt=\frac{Δt'}{\sqrt{1-\frac{u^{2}}{c^{2}}}}$