Spheres on a cone

Geometry Level 3

Three spherical balls are placed inside an inverted right circular cone such that each ball is in contact with the cone and the next ball. If the radii of the balls are 16, x, and 5.76 (in decreasing order), respectively, what is the ratio of the volume of the largest ball to the volume of the ball at the middle?

125 27 \dfrac{125}{27} 5 3 \dfrac{5}{3} 105 19 \dfrac{105}{19} 59 5 \dfrac{59}{5}

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1 solution

Consider the diagram on the left.

Using similar triangles, we have

16 x 16 + x = x 5.76 x + 5.76 \dfrac{16-x}{16+x}=\dfrac{x-5.76}{x+5.76}

Cross-multiplying and simplifying, we get

( 16 x ) ( x + 5.76 ) = ( 16 + x ) ( x 5.76 ) (16-x)(x+5.76)=(16+x)(x-5.76)

16 x + 92.16 x 2 5.76 x = 16 x 92.16 + x 2 5.76 x 16x+92.16-x^2-5.76x=16x-92.16+x^2-5.76x

x 2 = 92.16 x^2=92.16

x = 9.6 x=9.6

The ratio of the volumes is 1 6 3 9. 6 3 = \dfrac{16^3}{9.6^3}= 125 27 \boxed{\dfrac{125}{27}}

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