How many non-integral real numbers satisfy the above equation?
Notations :
denotes the fractional part function .
denotes the floor function .
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Relevant wiki: Floor and Ceiling Functions - Problem Solving
Let x = A + 2 0 1 k where k , A ∈ Z and 1 ≤ k ≤ 2 0 0 .
Then the equation is equivalent to k + 6 A = 2 0 1 6 . Note that ( k , A ) = ( 6 , 3 3 5 ) is a solution. Hence ( k , A ) = ( 6 + 6 m , 3 3 5 − m ) , where 1 ≤ 6 + 6 m ≤ 2 0 0 , are solutions. So 0 ≤ m ≤ 3 2 and thus there are 3 3 solutions.