Splitting the Square

Algebra Level 1

Find an equivalent expression for 3 6 2 . \large 36^2.

Note: While you can do this on a calculator, try to work it out without one! This can generalize into a method for squaring numbers mentally.

( 30 × 42 ) + ( 2 × 6 ) (30 \times 42) + (2 \times 6) ( 30 × 42 ) + ( 6 × 6 ) (30 \times 42) + (6 \times 6) ( 40 × 42 ) ( 6 × 6 ) (40 \times 42) - (6 \times 6) ( 40 × 42 ) ( 2 × 6 ) (40 \times 42) - (2 \times 6) ( 40 × 42 ) ( 2 × 2 ) (40 \times 42) - (2 \times 2)

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3 solutions

Zico Quintina
Jun 19, 2018

The idea is to change the number to be squared, call it n n , into a near multiple of 10 10 through either addition or subtraction, and then make use of the difference of squares pattern to re-write n 2 = ( n + α ) ( n α ) + α 2 n^2 = (n + \alpha)(n - \alpha) + \alpha^2 . In the given example, we can either use 36 + 4 = 40 36 + 4 = 40 or 36 6 = 30 36 - 6 = 30 . Then either

x 2 = ( x + 4 ) ( x 4 ) + 4 2 3 6 2 = ( 36 + 4 ) ( 36 4 ) + 16 = ( 40 × 32 ) + 16 = 1280 + 16 = 1296 x^2 = (x + 4)(x - 4) + 4^2 \quad \implies 36^2 = (36 + 4)(36 - 4) + 16 = (40 \times 32) + 16 = 1280 + 16 = 1296

or

x 2 = ( x 6 ) ( x + 6 ) + 6 2 3 6 2 = ( 36 6 ) ( 36 + 6 ) + 36 = ( 30 × 42 ) + 36 = 1260 + 36 = 1296 x^2 = (x - 6)(x + 6) + 6^2 \quad \implies 36^2 = (36 - 6)(36 + 6) + 36 = (30 \times 42) + 36 = 1260 + 36 = 1296

The latter is the calculation given in the answer choices; I might have used the former but it makes little difference.

Naren Bhandari
Jun 18, 2018

If A A number then let Y Y represents the unit place digit and X X represents the remaining digits then A 2 = ( 10 X + Y ) 2 = ( 10 X ) 2 + 20 X Y + ( Y ) 2 A 2 = 10 X ( 10 X + 2 Y ) + Y 2 = 10 X ( A + Y ) + Y 2 A^2 = (10X+ Y)^2 =(10X)^2 +20XY +(Y)^2\\ A^2 =10X(10X+2Y)+Y^2=10X(A+Y) +Y^2 Thus, 3 6 2 = 30 × ( 36 + 6 ) + 6 2 = ( 30 × 42 ) + ( 6 × 6 ) 36^2=30\times(36+6)+6^2 =(30×42)+(6×6)

Samrit Pramanik
Jun 19, 2018

For any a , b R \huge\text{For any} \;a,b \in \mathbb{R} a 2 = ( a + b ) ( a b ) + b 2 = a 2 b 2 + b 2 \huge a^2=(a+b)(a-b)+b^2=a^2-b^2+b^2

Here, a = 36 , b = 6 \Large a=36,\,b=6

Could you do an extra algebra step justifying why those are equal?

Jason Dyer Staff - 2 years, 11 months ago

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