Point A has the coordinates (4,37). This point forms a corner of a triangle with B and C, both of which lie on the line 3y-2x=12 and are equidistant from A, forming an isosceles triangle. If px+qy=r is the line of reflection of this triangle, for coprime positive integers p,q,r, what is p+q+r?
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The line which cuts the isosceles in half will pass through a and be perpendicular to 3y-2x=12 by nature. N.B. it does not matter where points B and C specifically are on the line. Thus the gradient of the perpendicular will be the negative reciprocal of the other line, which has a gradient of 2/3. So the gradient of the perpendicular will be -1.5. Then, using either y=mx+c (37=-1.5(4)+c) or y-37=-1.5(x-4), we can rearrange this to get 3x+2y=86. And so 3+2+86=91.