Evaluate:
3 0 + 3 0 + 3 0 + 3 0 + 3 0 + 3 0 + . . .
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Did it the same way... :)
Great answer dude
suppose let it be a terminating sequence answer will be sqrt(30n).n is the number of sqaureroots or thirties.....the answer will tend towards six for a non terminating sequence.
3 0 + 3 0 + 3 0 + 3 0 + 3 0 + 3 0 + ⋯ 3 0 + x 3 0 + x x 2 − x − 3 0 ( x − 5 ) ( x + 6 ) x 3 0 + 3 0 + 3 0 + 3 0 + 3 0 + 3 0 + ⋯ = l e t = = = = = = x x x 2 0 0 5 ( x > 0 ) 5
Problem Loading...
Note Loading...
Set Loading...
Let 3 0 + 3 0 + 3 0 + ⋯ = x .
Then, x = 3 0 + x .
So, x 2 − x − 3 0 = 0 , which can be factored into ( x − 6 ) ( x + 5 ) = 0 .
We take the quadratic's positive root to be our answer (since we want the principal square root), so x = 6 .