The largest square which can be covered completely with four unit squares is a square, as shown on the left.
Without cutting or bending the unit squares, what is the side length (to 3 decimal places) of the largest square that can be covered completely with three unit squares?
Disclaimer: The image on the right is not necessarily the right configuration to obtain the largest square.
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Any complete covering of a larger square by 3 unit squares is going to partition the perimeter of the larger square into at least 3 segments. Suppose one of them covers one segment. The maximum segment any one square can cover has a length of 2 , which occurs when one of the unit squares shares one same vertex with the larger square and is aligned with it---as the graphic shows. Then it's a matter of how much more the other two unit squares can cover.
If S is the side length of the larger square, and point P has the coordinates ( x , y ) , then if we let s = x y , point Q has the coordinates
Q = ( s 2 + 1 S , s s 2 + 1 S )
then we have the following system of equations to solve for x , y , s , S
x 2 + x 2 = 1
s = x y
− s 1 ( S − x ) + y = S − 1
( S − s s + 1 S ) 2 + ( s s s + 1 S ) 2 = 1
which yields the result
S = 2 1 + 5 = 1 . 2 7 2 0 2 . . .