Square for noobs

Geometry Level 3

An equilateral triangle has 20 cm side length. It is inscribed in a square. What's the length of the side of the square?

19.32 18.5 18 15.82

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2 solutions

By the pythagorean theorem ,

2 0 2 = x 2 + ( x + y ) 2 20^2=x^2+(x+y)^2 \color{#D61F06}\implies 400 = x 2 + x 2 + 2 x y + y 2 400=x^2+x^2+2xy+y^2 \color{#D61F06}\implies 400 = 2 x 2 + 2 x y + y 2 400=2x^2+2xy+y^2 ( 1 ) \color{#3D99F6}\large (1)

By the pythagorean theorem again,

2 0 2 = y 2 + y 2 20^2=y^2+y^2 \color{#D61F06}\implies 400 = 2 y 2 400=2y^2 \color{#D61F06}\implies 200 = y 2 200=y^2 ( 2 ) \color{#3D99F6}\large (2)

It follows that y = 200 14.142 y=\sqrt{200}\approx 14.142

Substitute ( 2 ) \color{#3D99F6}\large (2) and y 14.142 y \approx 14.142 in ( 1 ) \color{#3D99F6}\large (1)

400 = 2 x 2 + 2 x ( 14.142 ) + 200 400=2x^2+2x(14.142)+200 \color{#D61F06}\implies 200 = x 2 + 14.142 x + 100 200=x^2+14.142x+100 \color{#D61F06}\implies x 2 + 14.142 x 100 = 0 x^2+14.142x-100=0

Using the quadratic formula to solve for x x , we get, x = 5.176 x=5.176

Finally,

x + y = 5.176 + 14.142 = x+y=5.176+14.142= 19.32 \boxed{19.32}

Hana Wehbi
Jul 10, 2017

Using Pythagoras theorem, we have 2 y 2 = 400 y 2 = 200 y = 14.142 2y^2= 400\implies y^2=200 \implies y=14.142 .

Also: ( x 2 ) + ( x + y ) 2 = 400 (x^2)+(x+y)^2= 400 , substitute the value of y y in this equation and solve for x x , gives x = 5.176 s = 19.32 x= 5.176 \implies s=19.32 , where s s is the side of the square.

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