Square of the other

acc. to question the root of the eqation eqal to m and m^2

Now>>>> $\frac{-b}{a}=m(m+1)............................eqation1$ $\frac{c}{a}=m^{3}............................eqation2$

from eqation 1 and 2 ......we get value of $\frac{-b}{c}=\frac{m^2+m}{m^3}$

$a(m^2+m)=-b$ now putting the value of m from eqation 2 here we get $-b=a^2c^\frac{1}{3}+c^2a^\frac{1}{3}...................eqation3$

NOW putting the value of m from eq2 to ax^2+bx+c we wil get

$b^3+a^2c+ac^2=-3ac(a^2c^\frac{1}{3}+c^2a^\frac{1}{3})$

so using eqation3 we get the result as 3abc

on substituting a,b,c=1..we get w,w^2 as root s of the equation....then put the value and get the result