Square root of logarithms

Algebra Level 2

2 log 2 3 3 log 3 2 = ? 2^{\sqrt{ \log_2 3 }} - 3^{\sqrt{\log_3 2}} = \, ?


The answer is 0.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Arman Isajanyan
Dec 2, 2017

Note, that 2^\sqrt{log_{2} 3} = (2^{log_{2} 3})^{\frac{1}{\sqrt{log_{2} 3}}} = 3^\sqrt{\frac{1}{\log_{2} 3}} = 3^\sqrt{log_{3} 2} . As both members of expression are equal, the answer is 0.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...