Square root value

Algebra Level 2

{ x + 4 y = 11 x x + 64 y y = 539 \begin{cases} \sqrt x+4\sqrt y=11 \\ x\sqrt x+64y\sqrt y=539 \end{cases}

Given x x and y y satisfy the system of equations above, what is x + 16 y 4 x y = ? x+16y-4\sqrt{xy}=?


The answer is 49.

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2 solutions

Chew-Seong Cheong
Apr 11, 2019

x x + 64 y y = 539 Given ( x ) 3 + ( 4 y ) 3 = 539 Since a 3 + b 3 = ( a + b ) ( a 2 a b + b 2 ) ( x + 4 y ) ( x 4 x y + 16 y ) = 539 Given that x + 4 y = 11 x + 16 y 4 x y = 539 11 = 49 \begin{aligned} x\sqrt x + 64 y\sqrt y & = 539 & \small \color{#3D99F6} \text{Given} \\ \color{#3D99F6} (\sqrt x)^3 + (4\sqrt y)^3 & = 539 & \small \color{#3D99F6} \text{Since }a^3+b^3 = (a+b) (a^2 - ab + b^2) \\ \color{#D61F06} (\sqrt x + 4\sqrt y)\color{#3D99F6} (x - 4\sqrt{xy} + 16y) & = 539 & \small \color{#D61F06} \text{Given that }\sqrt x + 4\sqrt y = 11 \\ \implies x + 16 y - 4\sqrt{xy} & = \frac {539}{\color{#D61F06}11} \\ & = \boxed {49} \end{aligned}

x + 4 y = 11 x x + 64 y y = 539 { x 64 , y 9 16 } , { x 9 , y 4 } \sqrt{x}+4 \sqrt{y}=11\land x \sqrt{x}+64 y \sqrt{y}=539 \Rightarrow \left\{x\to 64,y\to \frac{9}{16}\right\},\{x\to 9,y\to 4\} . Both solutions imply that the value of 4 x y + x + 16 y -4 \sqrt{x y}+x+16 y is 49 49 .

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