1 1 1 1 1 1 1 1 = ?
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The question is in the form of 1 1 1 1 1 1 1 1 , which may be rewritten as 1 1 1 1 1 1 2 3 , then 1 1 1 1 ( 1 1 4 3 ) , then 1 1 ( 1 1 8 7 ) , and finally, 1 1 1 6 1 5
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If we solve the expression we get 11^[1/2+1/4+1/8+1/6] solving this GP [1/2(1-1/16)]/(1/2)=15/16
Hence the answer is 11^15/16
1/6 → 1 6 1
Using calculator's method, ln 1 1 ln 9 . 4 6 9 0 3 3 2 6 6 9 9 5 3 1 5 8 4 5 9 9 9 0 3 6 4 3 9 9 3 4 + = 0 . 9 3 7 5
0.9375 × 16 = 15
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1 1 1 1 1 1 1 1 = ( 1 1 ( 1 1 ( 1 1 × 1 1 2 1 ) 2 1 ) 2 1 ) 2 1 = ( 1 1 ( 1 1 ( 1 1 2 3 ) 2 1 ) 2 1 ) 2 1 = ( 1 1 ( 1 1 × 1 1 4 3 ) 2 1 ) 2 1 = ( 1 1 × 1 1 8 7 ) 2 1 = 1 1 1 6 1 5