Squared Triangle

John drew a triangle such that all the angles, in degrees, were perfect squares. What was the largest angle among them, in degrees?


The answer is 100.

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6 solutions

Sam Reeve
Nov 25, 2015

100 + 64 + 16 100+64+16 .

Proof that there is only this solution.

Only possible squares are 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169.

If ( a 2 + b 2 = c 2 a^2+b^2=c^2 ) then ( c = s 2 + t 2 c=s^2+t^2 ) Also a square can only be of the form 4 n 4n or 4 n + 1 4n+1

Each square will leave a remainder from 180 which must be the sum of two squares.

Therefore we cannot have odd numbers

1 : odd

4 : 176 is 16*11, which has no solutions ( 4 a 2 + 4 b 2 = 4 n 4a^2+4b^2=4n so 11 would have to be a sum of two sqrs)

9 : odd

16 : 164

25 : odd

36 : 144 is square. But 12 cannot be expressed as sum of two squares (since 3 can't)

49 : odd

64 : 116

81 : odd

100 : 80

121 : odd

144 : 36 is square. But 6 has no solutions

169 : odd

So it could only be 16, 64 and 100. Which do add up to 180

Moderator note:

Great solution.

It could be cleaned up by presenting it in the following way:
1. Squares leave a remainder of 0 or 1 when divided by 4.
2. Hence, if one of the squares was odd, we cannot find 3 squares which sum to 180.
3. 144 doesn't work, because 180-144=36, and there are no solutions.
4. 4 doesn't work, because 180 4 = 176 = 11 × 16 180-4=176 = 11 \times 16 , and Fermat's two square theorem tells us that since 11 176 11 \mid 176 , hence no solutions exist.
5. Thus, we are only left with 16, 64, 100. Notice that these do add up to 180.


@Sam Reeve That's a great proof! I've converted your comment into a solution :)

Calvin Lin Staff - 5 years, 6 months ago
Xiaoying Qin
Nov 24, 2015

Using 3 perfect squares of 100, 64, and 16, which is 1 0 2 , 8 2 , 10^2, 8^2, and 4 2 4^2 , they will add up to 180.

Prove that this is the only possible solution.

Kushagra Sahni - 5 years, 6 months ago

Why 6 4 2 64^2 ?

Akshat Sharda - 5 years, 6 months ago

Log in to reply

Gosh I have too many errors!

Xiaoying Qin - 5 years, 6 months ago
Gareth Adamson
Nov 28, 2015

Starting from 169 (no triangle can have a > 180 degree angle), you can use simple proof by exhaustion in order to prove that 100 + 64 + 16 is the only possibility.

169 - No perfect squares add up to 11 (9+1 is the closest possible) 144 - No perfect squares add up to 36, as it is a perfect square itself 121 - No perfect squares add up to 59 (9 + 49 is closest possible) 100 - 64 + 16 works.

Therefore the solution is 100.

A Steven Kusuman
Nov 28, 2015

Meet In The Middle approach :v

Oli Hohman
Nov 28, 2015

Sum of angles of triangle is 180 degrees a^2+b^2+c^2 = 180 You know a,b,c < 14 because 14^2 = 196

Testing 13^2 ---> 180-13^2 = 11 and no two squares combine to make 11 Testing 12^2 ---> 180-12^2 = 36 and no two squares combine to make 36 Testing 11^2 ---> 180-11^2 = 59 and no two squares combine to make 59 Testing 10^2 ---> 180-10^2 = 80

a^2+b^2 = 80

80 = 4^2+8^2

Therefore, the largest angle of this triangle is 10^2 degrees = 100 degrees

My method: 180 can write into square number times constant in 2 way, they are 9*20 and 4 \times 45 .

I check out only square 1 4 9 16 25 36 .

for 9*20 I can't write 20 with sum of three square numbers.

but in case of 4*45.

I can make 45 by 4+16+25.

so, 180 = 4 45 = 4 4 +4 16 +4 25 =4^2+8^2+10^2.

therefore 10^2 = 100 is the largest angle.

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