The sum of the squares of five consecutive positive integers is 9255. What is the value of the square of the next integer?
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Let the numbers be x-2, x-1, x, x+1, x+2. Sum of squares of the numbers is 5x^2 +10 or 9255. This gives us x =43. We require square of x+3 or 46^2, i.e. 2116