Squares!

Algebra Level 2

The sum of the squares of five consecutive positive integers is 9255. What is the value of the square of the next integer?


The answer is 2116.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Ankur Agarwal
Oct 14, 2014

Let the numbers be x-2, x-1, x, x+1, x+2. Sum of squares of the numbers is 5x^2 +10 or 9255. This gives us x =43. We require square of x+3 or 46^2, i.e. 2116

i did the same way

parth tandon - 6 years, 8 months ago
Fox To-ong
Jan 10, 2015

The integers are 41,42,43,44,45 and 46

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...