Squares and Roots IV

$\frac { \sqrt { 10 } }{ 10 } \times \frac { \sqrt { 8 } }{ 8 } = A$

$\frac { \sqrt { 80 } }{ 80 } =A$

$\frac { 80 }{ 6400 } ={ A }^{ 2 }$

$\frac { 1 }{ 80 } ={ A }^{ 2 }$

$\sqrt { \frac { 1 }{ 80 } } =A$

Details of given rectangle:

Length $= a = \frac{\sqrt{10}}{10}$

Breadth $= b = \frac{\sqrt{8}}{8}$

Area of rectangle $= ab$

$= \frac{\sqrt{10}}{10} \times \frac{\sqrt{8}}{8}$

$= \frac{\sqrt{10} \times \sqrt{8}}{10 \times 8}$

$= \frac{\sqrt{80}}{80} = \frac{\sqrt{80}}{\sqrt{80} \times \sqrt{80}} = \frac{1}{\sqrt{80}}$

Thus, area of rectangle $= \boxed{\frac{1}{\sqrt{80}}}$

we can write a=1/under root 10 and b+ 1/under root. Now are of rectangle is aXb that is 1/under root 80 Ans. K.K.GARG,India

its easy. you just need power of a and b

Area of rectangle = a b Here, a = root 10/10 b= root 8/8 Therefore, Area= (root 10/10) (root 8/8) = (root 10/root 100) (root 8/root 64) = [root ( 10/100)] [ root ( 8/64)] = { root [ (10/100) (8/64)]} = { root [ (1/10) (1/8)]} = { root [ 1/80]} = root ( 1/80)

Just base times height its also like 1/rt10 x 1/rt8

area =length*bredth so multiply both the uantities and you will get the answer

a = \frac{\sqrt{10}}{10} = \frac{1}{\sqrt{10}} b= \frac{\sqrt{8}}{8} = \frac{1}{\sqrt{8}} Thus area of rectangle = a \times b a \times b = \frac{1}{\sqrt{80}}

area=a*b a=1/root 10 and b=1/root 8 then area=1/root 80 ans

1/(10^0.5) 1/(8^0.5)=1/(10 8)^0.5=1/80

\­( ab=\frac { \sqrt { 10 } }{ 10 } x\frac { \sqrt { 8 } }{ 8 } \ \frac { \sqrt { 10 } }{ 10 } =\sqrt { \frac { 1 }{ 10 } } ,\quad \frac { \sqrt { 8 } }{ 8 } =\sqrt { \frac { 1 }{ 8 } } \Longrightarrow \quad ab=\quad \sqrt { \frac { 1 }{ 10 } } x\sqrt { \frac { 1 }{ 8 } } =\quad \sqrt { \frac { 1x1 }{ 10x8 } } =\sqrt { \frac { 1 }{ 80 } } \ \­)