Perfect square roots!

Algebra Level 1

If $x=144$ and $y=169$ , find the value of $\big(\sqrt{x}+\sqrt{y}\big)^2$ .

3 solutions

Skanda Prasad
Jun 7, 2016

We know that $x=144$ and $y=169$ . Hence, $\sqrt{144}=12$ and $\sqrt{169}=13$ .

According to the question, $(\sqrt{x}+\sqrt{y})^2$ is asked.

$\therefore (12 + 13)^2 = 25^2 = 625$

Hence, the answer.

You did it nicely. Thanks!

Sandeep Bhardwaj - 5 years ago

i wonder who did even this wrong

A Former Brilliant Member - 4 years, 10 months ago

Sonia Gupta
Jun 7, 2016

Did the same with the question!!!

Hi Sonia

This is not a solution. Kindly delete this.

In future, please use the Reply Button, in case you need to reply to a solution.

Thanks.

Mehul Arora - 5 years ago

Galen Buhain
Jul 25, 2016

( 12 + 13 ) squared is equal to 625