Squares in Triangles

Geometry Level 4

Let a triangle A B C ABC with B C = 6 cm BC = 6 \text{ cm} , and the area of 30 cm 2 30\text{ cm}^2 . A square P Q R S PQRS is inscribed so that points S S and R R is on B C BC , Q Q on A C AC , and P P on A B AB respectively. Find the side length of the square P Q R S PQRS .


The answer is 3.75.

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2 solutions

Alan Yan
Sep 12, 2015

( 6 + x ) x 2 + x ( 10 x ) 2 = 30 x = 15 4 = 3.75 \frac{(6+x)x}{2} + \frac{x(10-x)}{2} = 30 \implies x = \frac{15}{4} = \boxed{3.75}

Maria Kozlowska
Sep 12, 2015

Height of the triangle ABC can be computed as follows: 6 h / 2 = 30 h = 10 6*h/2=30 \Rightarrow h=10 . A B C is similar to A P Q P Q / ( 10 P Q ) = 6 / 10 P Q = 15 / 4 = 3.75 \triangle ABC \text{ is similar to } \triangle APQ \Rightarrow PQ/(10-PQ)= 6/10 \Rightarrow PQ=15/4=3.75

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