Without using a calculator, find the value of
8 1 0 0 0 0 0 0 0 0 1 8 0 0 0 0 0 0 0 0 0 1 .
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Forgot that breaking into addition will make it that simple!
Obviously, this would be easy with a calculator. But we shall never be ruled by machines.
To solve, we use the pattern
( a + b ) 2 = a 2 + 2 a b + b 2 .
In this question, there are three numerical components to the square number (separated nicely by zeroes), corresponding to the three components of ( a + b ) 2 . W.l.o.g., take a as the larger component of a + b . So we reason as follows, and hope for the best:
Since our answer is positive, this largest component must also be positive. So:
Now:
Given these values:
Since we see + 1 8 × 1 0 1 0 in our square number (and not 8 2 and loads of 9 s, as we would with a b negative), take
and just make sure:
( 9 0 0 0 0 0 0 0 0 0 1 ) 2
= ( 9 × 1 0 1 0 + 1 ) 2
= 8 1 × 1 0 2 0 + 2 ( 9 × 1 0 1 0 ) + 1
= 8 1 0 0 0 0 0 0 0 0 1 8 0 0 0 0 0 0 0 0 0 1 ,
as it should be.
So 8 1 0 0 0 0 0 0 0 0 1 8 0 0 0 0 0 0 0 0 0 1 = 9 0 0 0 0 0 0 0 0 0 1 .
8 1 0 0 0 0 0 0 0 0 1 8 0 0 0 0 0 0 0 0 0 1 = 8 1 × 1 0 2 0 + 1 8 × 1 0 1 0 + 1 = ( 9 × 1 0 1 0 ) 2 + 2 ( 9 × 1 0 1 0 ) ( 1 ) + 1 2 = ( 9 × 1 0 1 0 + 1 ) 2 = 9 × 1 0 1 0 + 1 = 9 0 0 0 0 0 0 0 0 0 1
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Sir, idol ko po kau sir =) . ang lufet..
(9^10 + 1)^2 = 90000000001^2 Therefore Root of 8100000000180000000001 = 90000000001
99=81 9+9=18 so we will use " a^2 + 2ab + b^2 " , a ^2 =( 9 * 10^ 10 )^2 b^2 = 1 2ab = 2(910^101) so, by applying on the pattern : 8110^20 + 1810^10 + 1 = the number above by sqrt both the number and the pattern that gives us (9*10^10 + 1) 90000000001
9 9=81 9+9=18 so we will use " a^2 + 2ab + b^2 " , a ^2 =( 9 * 10^ 10 )^2 b^2 = 1 2ab = 2 (9 10^10 1) so, by applying on the pattern : 81 10^20 + 18 10^10 + 1 = the number above by sqrt both the number and the pattern that gives us
90000000001
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8 1 0 0 0 0 0 0 0 0 1 8 0 0 0 0 0 0 0 0 0 1 = 8 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 + 2 × 9 0 0 0 0 0 0 0 0 0 0 × 1 + 1 = ( 9 0 0 0 0 0 0 0 0 0 0 + 1 ) 2 = 9 0 0 0 0 0 0 0 0 0 1