There is a unit circle with its center point at
.
There is a set of 4 linear functions in the form:
which intersect the circle at 8 points. There is a square that intersects the unit circle at the same 8 points with sides parallel to X and Y axis.
If
is semi-perimeter of the square then
.
Find the set of smallest positive integer numbers such that they meet the described criteria. Find all the prime factors of numbers and . For each factor , find which is number of primes equal to or less then . Give answer as a product of all .
Details and Assumptions:
If some prime number appears more than once as a factor use it only once in the solution, i.e. if has prime factors: and has prime factors: , use only numbers in calculating the final answer which in this case would be . The problem is original.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
The values 2 × 1 4 2 3 , 2 2 4 3 will produce such a square. The result is 2 2 4 × 3 3 4 = 7 4 8 1 6 .
I think it is quite interesting result; all digits are 1 − 4 . If someone has some explanation for these numbers please post.