Start from the very basic definition!

Algebra Level 3

e ln { x } { x } 1 / ln { x } \large { e }^{ -\sqrt { \left| \ln\{ x\} \right| } }-{ \{ x\} }^{ 1/\sqrt { \left| \ln\{ x\} \right| } }

Evaluate the expression above for x 0 x\ne 0

Notation : { } \{ \cdot \} denotes the fractional part function .


The answer is 0.

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1 solution

Chew-Seong Cheong
Aug 22, 2017

X = e ln { x } { x } 1 ln { x } = e ln { x } e ln { x } ln { x } = e ln { x } e ln { x } ln { x } = e ln { x } e ln { x } = 0 \large \begin{aligned} X & = e^{-\sqrt{|\ln \{x\}|}} - \{x\}^{\frac 1{\sqrt{|\ln \{x\}|}}} \\ & = e^{-\sqrt{|\ln \{x\}|}} - e^{\frac {\ln \{x\}}{\sqrt{|\ln \{x\}|}}} \\ & = e^{-\sqrt{|\ln \{x\}|}} - e^{\frac {-|\ln \{x\}|}{\sqrt{|\ln \{x\}|}}} \\ & = e^{-\sqrt{|\ln \{x\}|}} - e^{-\sqrt{|\ln \{x\}|}} \\ & = \boxed{0} \end{aligned}

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