Started learning Permutations!
Probability
Level
2
How many cars are there with numbers like GJ-X-AB-abcd where X is an digit from 1 to 9;A is H,B is one of the alphabets in English and abcd is a four digit number? (a can be zero)
The answer is 2339766.
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1 solution
X is an digit from 1 to 9,So 9 there are 9 ways to select X..
B can be anyone of the 26 alphabets,So there are 26 ways to select B...
Now in abcd
a can be anyone from1-10.. b can be anyone from 1-10... c can be anyone from 1-10.... d can be anyone from 1-10....
So there are 10000 ways for selecting abcd...
But we need to subtract the number 0000 from this, So there are 9999 ways for selecting abcd...
So finally there are 9×26×9999=2339766 cars....