Static Charged Particles on a Wire

In the x y xy -plane, there is a semi-infinite wire in the shape of the curve y = x y = x .

Particle 1, with mass and charge ( m 1 = 0 kg , q 1 = + 1 0 4 C ) \big(m_1 = 0 \text{ kg}, q_1 = +10^{-4} \text{ C}\big) , is fixed at the origin.
Particle 2, with mass and charge ( m 2 = 1 kg , q 2 = + 1 0 4 C ) \big(m_2 = 1 \text{ kg}, q_2 = +10^{-4} \text{ C}\big) , can slide freely along the wire.

There is a uniform downward gravitational acceleration g = 10 m / s 2 g = \SI[per-mode=symbol]{10}{\meter\per\second\squared} .
The Coulomb constant is k e = 9 × 1 0 9 N m 2 / C 2 k_e = \SI[per-mode=symbol]{9e9}{\newton\meter\squared\per\coulomb\squared} .

If Particle 2 is in static equilibrium, what is the x x -coordinate of its position (in meters, to 2 decimal places)?


The answer is 2.52.

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1 solution

Prakhar Bindal
Nov 19, 2016

Equate the force due to gravity and the electrostatic force of repulsion along the line y=x

Let the position of particle is (x,x)

kq1q2/2x^2 = 10*sin(45)

from here x = 3/2^(0.25)

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