Still more Diophantine equations

Algebra Level pending

How many real solutions are there to the following system of equations? a = a 2 + 2 b c a=a^{2}+2bc b = b 2 + 2 a c b=b^{2}+2ac c = c 2 + 2 a b c=c^{2}+2ab


The answer is 8.

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1 solution

Abhijit Dixit
Mar 6, 2017

Add all the equations to get

a + b + c = 0 a+b+c=0 OR . a + b + c = 1 a+b+c=1

Put c = a b c= -a-b in all three equations. And solve for a , b a,b

From this you will get 4 solutions.

Again put c = a b + 1 c= -a-b +1 in all three equations. And solve for a , b a,b

From this you will get 4 more solutions.

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