Stones on my head
Classical Mechanics
Level
2
A body is released from a height and it falls towards the earth. Exactly 1 second later another body is released. What is the distance between the 2 bodies 2 seconds after the release of the second body?
24.5m
9.8m
4.9m
50m
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1 solution
The distance travelled by a freely falling body is equals to 4 . 9 t 2 .
Since the first stone is released 1 sec earlier therefore the time difference is 1 sec. Let the time after being released for
Stone 1= T 1 and
Stone 2= T 2 . After two seconds, T 1 =3 sec and T 2 =2 sec.
Acc. to the formula, Distance travelled by stone 1 =4.9 T 1 2 =4.9×9
Distance travelled by stone 2 =4.9 T 2 2 =4.9×4 The fore the distance between them.
=4.9×9-4.9×4
=4.9(9-4)
=4.9×5
=24.5m