A driver applies breaks after seeing an accident site 400m ahead.At the instant he applies the breaks ,the vehicle was moving with a speed of 15m/s and after it started to retard with 0.3m/s^2 .Find the distance of vehicle after 1 minute ,from the accident site(Answer in metre)?
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u=15,r=0.3 v^2 - u^2=2as since final velocity v =0, thus u^2=2as s=u^2/2r = 375 v=u+at u=at t= 15/0.3 =50 s after 50 s it comes to a halt so distance from site=400-375=25