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If n = 3 * 7 * 11 * 15 * 19 * ............ * 2003. Find the last three digit of n.


The answer is 875.

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1 solution

Vishnu Prasad
Jul 28, 2015

In the above sequence we have 201 terms.... product of 5x5x5x5=625 that means in groups of five terms we have one multiple of 5 ...so product four groups leads to 625 as last three digits... we have 50 groups +0ne term(2003) 50 groups gives 625 as last three digit . so simply 625 3 or 625 2003 give last three digits as 875

how can i believe the solution is true?

Srinivasteja Vemuru Thiru - 3 years, 7 months ago

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