Straightforward but don't get tricked!

Calculus Level 1

What is:

$\large \frac {d}{dx} \ln (2018x)$

2018 \times \frac {1}{x}

\ln x

\frac {1}{x}

\ln (2018x)

2 solutions

Robert Szafarczyk
May 7, 2018

$\ln (2018x) = \ln 2018 + \ln x$ therefore $\frac {d}{dx} \ln (2018x) = \frac {d}{dx} \ln x = \frac {1}{x}$ ( $\ln 2018$ is a constant)).

Hana Wehbi
May 8, 2018

$\frac{d}{dx}\ln(u(x))=\frac{u’(x)}{u(x)}\implies \frac{d}{dx}(2018x) = \frac{2018}{2018x}=\frac{1}{x}$