When we toss 5 fair coins, which sequence is more likely to happen?
A: Getting 2 heads
B: Getting 4 heads
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It can solved by the famous binomial distribution.
P(2H)= 5C2 (1/2)^2 (1/2)^3,
P(4H)= 5C4 (1/2)^4 (1/2)^1
Now,
P(2H)/P(4H)= 2.