A four-digit number of the form has a special property such that .The number is a divisor of all these numbers of this form.Also, is an odd prime positive integer.Find .
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The question states that...
a + c = b + d ⟹ b + d − a − c = 0
Now notice that...
a b c d = 1 0 0 0 a + 1 0 0 b + 1 0 c + d
= ( 1 0 0 1 a + 9 9 b + 1 1 c ) + ( b + d − a − c )
= 1 0 0 1 a + 9 9 b + 1 1 c + 0
= 1 1 ( 9 1 a + 9 b + c )
Since 1 1 is an odd prime positive integer, we are done. Therefore...
n = 1 1