The value of π is approximated using the following complex fraction:
π ≈ k 1 + k 2 + k 3 + k 4 + k 5 1 1 1 1
There are, however, a couple of constraints to the constants k 1 , k 2 , k 3 , k 4 , k 5 :
If the value of this complex fraction is equal to b a , where a and b are relatively prime integers (that is, g cd ( a , b ) = 1 ), what is a + b ?
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The complex fraction above is a segment of the continued fraction representation of π :
π ≈ 3 + 7 + 1 5 + 1 + 2 9 2 + . . . 1 1 1 1
The derivation of the continued fraction representation of π can be found at this stack exchange post .
Substituting k 1 = 3 , k 2 = 7 , k 3 = 1 5 , k 4 = 1 , k 5 = 2 9 2 ( ∑ n = 1 n = 5 k n = 3 1 8 ) into the given complex fraction and simplifying into a single fraction yields 3 3 1 0 2 1 0 3 9 9 3 . The numerator and denominator are relatively prime ( g cd ( 1 0 3 9 9 3 , 3 3 1 0 2 ) = 1 ) to each other and ∣ π − 3 3 1 0 2 1 0 3 9 9 3 ∣ = 5 . 7 7 8 9 ∗ 1 0 − 1 0 , therefore the answer is 1 0 3 9 9 3 + 3 3 1 0 2 = 1 3 7 0 9 5 .