A hammer of mass
falls from a height
to strike a pile of mass
into ground. Pile penetrates a distance
in a single blow. Find the resistance to penetration given by ground in
Details and Assumptions
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Velocity of hammer at the time of contact will be 2 g l Apply law of conservation of momentum ( M + m ) v = M 2 g l ⇒ v = ( M + m ) M 2 g l
We know that work done by a force equals force times displacement.
And of course everyone knows about work energy theorem
R × d − ( M + m ) g d = 2 1 ( M + m ) ( ( M + m ) M 2 g l ) 2 ⇒ R = ( M + m ) d M 2 g l + ( M + m ) g Plug in the values now.