String tension

Classical Mechanics Level 3

A $1.5 \text{ m}$ long string can endure a tension force of $50 \text{ N.}$ An object with mass $3.0 \text{ kg}$ attached to this string is in uniform circular motion in a horizontal orbit. Find the maximum speed of this object (in m/s).

Gravitational acceleration is $g= 10 \text{ m/s}^2.$

6 \text{ m/s}

5 \text{ m/s}

3 \text{ m/s}

8 \text{ m/s}

1 solution

Hjalmar Orellana Soto
Jul 19, 2016

In this situation, we have the Tension as centripetal force. So we have $T=F_{c}=m\frac{v^2}{R}$ . From there we know that $T\propto v^2$ , so the maximum speed will be reached when Tension is maximum ( $T=50[N]$ ). So, we have: $50[N]=3[kg]\cdot \frac{v^2}{1,5[m]} \Rightarrow v=5[m/s]$

String tension

1 solution

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