Struggler's Geometry problem

Geometry Level 2

In triangle ABC in the diagram above,D and E are points on side {AB}, and F and G are points on side {AC}, AD = DG = GB = BC = CE = EF = FA. Find angle BAC

25+ 9 7 \frac{9}{7} . 23 25+ 5 7 \frac{5}{7} . 22 25+ 4 7 \frac{4}{7} .

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1 solution

From the diagram it is clear that B = C = 3 A \angle B=\angle C=3\angle A . Hence 7 A = π 7\angle A=π or A = π 7 \angle A=\dfrac{π}{7} . In degree unit, A = 180 7 = 25 + 5 7 \angle A=\dfrac{180}{7}=25+\dfrac{5}{7}

I don't get how angle B and C are 3 times the angle A.

Justin Park - 1 year, 7 months ago

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