A hypotenuse of a right triangle is c = 2 0 and the area of the triangle is 1 0 0 .
If the other two sides are a and b , find the value of ∣ a − b ∣ .
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Solution:
Area: 1 0 0 = 2 c × h c ⇒ h c = 1 0 .
Since, h c = 2 c right triangle is also an isosceles one, meaning a = b .
Solution: 0 .
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G i v e n : a 2 + b 2 = c 2 = 4 0 0 a n d 2 × a b = 4 × A r e a = 4 0 0 ∣ a − b ∣ = a 2 + b 2 − 2 a b = 4 0 0 − 4 0 0 = 0