How many odd 3-digit numbers are there in base 9?
Details and assumptions
A number is odd if it is not divisible by 2.
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Solution 1: There are 9 choices for each of the second and third digits. For the first digit, if the existing 2-digit number is odd, we have 4 choices (2,4,6,8) and if the existing 2-digit number is even, we have 4 choices (1,3,5,7). Thus, there are a total of 9 ∗ 9 ∗ 4 = 3 2 4 such numbers.
Solution 2: Since 1 0 0 3 = 8 2 and 9 9 9 3 = 7 2 9 , hence there are 2 7 2 9 − 8 3 + 1 = 3 2 4 odd numbers.