Pandigital madness

Find the value of the number above (up to 3 3 decimal places).


The answer is 2.718.

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1 solution

Vighnesh Raut
Dec 19, 2017

The number can be manipulated to be written as ( 1 + 1 3 2 85 ) 3 2 85 { (1+\frac { 1 }{ { 3 }^{ { 2 }^{ 85 } } } ) }^{ { 3 }^{ { 2 }^{ 85 } } } which is of the form ( 1 + 1 n ) n { (1+\frac { 1 }{ n } ) }^{ n } . We know that for very large n n , ( 1 + 1 n ) n { (1+\frac { 1 }{ n } ) }^{ n } approaches e e .

It is an example for a pandigital number. Pandigital numbers are the numbers which have all the digits from 1 1 to 9 9 inclusive. 0 0 is optional, sometimes it is preferred and sometimes it isn't. The above illustrated number is a very incredible formula. Incredible because it is a very good approximation for e e , up to 18 18 trillion trillion digits. To know more about it, check this Numberphile's video.

Does 3 4 42 = 3 2 85 or is it equal to 3 2 84 \large 3^{{-4}^{42}} = 3^{{2}^{-85}} ~\text{or is it equal to}~ 3^{{2}^{-84}}

Vilakshan Gupta - 3 years, 5 months ago

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( 3 2 ) 4 42 = ( 3 2 ) 2 84 = 3 2 85 { { ( }3^{ 2 }) }^{ { -4 }^{ 42 } }={ { ( }3^{ 2 }) }^{ { -2 }^{ 84 } }={ 3 }^{ { -2 }^{ 85 } }

Vighnesh Raut - 3 years, 5 months ago

damn your love for powers is still same and intact. Great Question! :D

Harshvardhan Mehta - 3 years ago

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Haha.. Some things never change.. Glad to see u here after a long time...

Vighnesh Raut - 2 years, 11 months ago

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