Sum of a Harmonic Progression

Algebra Level pending

Find the sum of the harmonic progression below. Choose the nearest value among the choices.

1 5 + 1 10 + 1 15 + . . . + 1 100 + 1 105 \dfrac{1}{5}+\dfrac{1}{10}+\dfrac{1}{15}+...+\dfrac{1}{100}+\dfrac{1}{105}

-0.7 0.7 7 -7

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2 solutions

Chew-Seong Cheong
May 12, 2020

The sum is k = 1 21 1 5 k \displaystyle \sum_{k=1}^{21} \frac 1{5k} , which we can estimate as 1 5 0.5 20.5 1 x d x = 1 5 ( ln ( 20.5 ) ln ( 0.5 ) ) 0.7 \displaystyle \frac 15 \int_{0.5}^{20.5} \frac 1x\ dx = \frac 15 (\ln(20.5)-\ln(0.5)) \approx \boxed{0.7} .

One way is to find the sum of 5 + 10 + 15 + 20 + 25 + 30 + 35 + 40 + 45 + 50 + 55 + 60 + 65 + 70 + 75 + 80 + 85 + 90 + 95 + 100 + 105 = 1155 5 + 10 + 15 + 20 + 25 + 30 + 35 + 40 + 45 + 50 + 55 + 60 + 65 + 70 + 75 + 80 + 85 + 90 + 95 + 100 + 105 = 1155 .

Then 115 5 1 1155^{-1} = 1 1155 \frac{1}{1155} = 0.00086580086 = 0.00086580086 .

Since it's a positive decimal, the nearest answer from the multiple-choice is 0.7 0.7 .

Therefore the answer is 0.7 0.7 .

This solution is wrong. Yes it is true that harmonic progression is the reciprocal of arithmetic progression, but it does not mean that it is also the reciprocal of the sum.

Marvin Kalngan - 1 year, 1 month ago

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I know that but I am a GCSE student. @Marvin Kalngan

A Former Brilliant Member - 1 year, 1 month ago

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