Sum of angles

Geometry Level 2

Find a + b + c + d + e a+b+c+d+e in the pentagram shown above.

90 180 270 540 360

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1 solution

Consider the diagram on the above.

v = 180 ( b + d ) v=180-(b+d)

w = 180 ( c + e ) w=180-(c+e)

x = 180 ( a + d ) x=180-(a+d)

y = 180 ( b + e ) y=180-(b+e)

z = 180 ( a + c ) z=180-(a+c)

We know that v + w + x + y + z = 540 v+w+x+y+z=540 . So

180 ( b + d ) + 180 ( c + e ) + 180 ( a + d ) + 180 ( b + e ) + 180 ( a + c ) = 540 180-(b+d) + 180-(c+e) + 180-(a+d) + 180-(b+e) + 180-(a+c) = 540

900 2 ( a + b + c + d + e ) = 540 900 - 2(a+b+c+d+e)=540

900 540 = 2 ( a + b + c + d + e ) 900-540=2(a+b+c+d+e)

360 = 2 ( a + b + c + d + e ) 360=2(a+b+c+d+e)

a + b + c + d + e = a+b+c+d+e= 180 \boxed{180}

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