Sum of binoms

For $\binom{n}{0}+$ $\binom{n}{1}+$ $\binom{n}{2}+$ $\dots{}+$ $\binom{n}{n}=$ we have $\text{2}^{n}$

Thus for $\binom{18}{0}+$ $\binom{18}{1}+$ $\binom{18}{2}+$ $\dots{}+$ $\binom{18}{18}=x$

$\text{}x={2}^{18}=262144$

$\therefore$ the answer is $\boxed{\color{#302B94}{262144}}$