Sum of Coeffeicient

Given a generic polynomial $p(x)=a_nx^n+a_{n-1}x^{n-1}+...+a_1x+a_0$ ,

we notice that $p(1)=a_n+a_{n-1}+...+a_1+a_0$

which is exactly the sum of coefficients.

In this case: $p(1)=(11\cdot 1-10)^{2018} =\boxed{1}$