Sum of digits problem

Let S ( x ) S(x) be the sum of digits of the positive integer x x in its decimal representation. Let maximum value of S ( x ) S ( 2 x ) \frac{S(x)}{S(2x)} be M M . Find the value of M M .


The answer is 5.00.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Rajdeep Brahma
May 23, 2018

The maximum carry is 1.This implies the only carries in 2x are the ones accounted for in S(2d) for each digit d in the decimal representation of x.Hence S(2x)= \sum S(2d),where the sum is taken over all the digits of x.It is clear that S ( d ) S ( 2 d ) \frac{S(d)}{S(2d)} <= 5 for every decimal digit d not equal to 0.Thus S ( x ) S ( 2 x ) \frac{S(x)}{S(2x)} <=5.The equality holds if x=5 and hence the bound can not be improved. Another way I want u people to think is in the way that S(x)=S(10x)....then????.....10=5*(2x) use and see...want some one to solve in this manner... :).

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...