I have 6 bags, each bag contains a non-zero amount of marbles such that:
the 2nd bag contains twice as many marbles as the 1st bag,
the 3rd bag contains twice as many marbles as the 2nd bag,
the 4th bag contains twice as many marbles as the 3rd bag,
the 5th bag contains twice as many marbles as the 4th bag,
the 6th bag contains twice as many marbles as the 5th bag.
What is the minimum total number of marbles used in these 6 bags?
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That's tricky. I didn't expect to put bags within bags.
Haha... @Pi Han Goh ...I like that! I just kept wondering why the answer isn't 63...love it!! Do keep more of such problems coming!!!
Whoa nice one. I put 6 3 at first, took me several minutes to see the solution. :)
Narrative of the question was misleading
The phrasing was misleading to the extent that I'd say an answer of 32 is based on a huge assumption. Nothing in the question suggests that the narrative is bags within bags. Might wanna make that clearer for future problems. =)
That aside, nice question! Would have been great to attempt!
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I sort of agree with you. Some fool who does not know how to compute a simple geometric progression (and who did not read the problem well) might have answered 32 purely because that is what he expects the 6th bag to contain. I almost guessed 32 myself just because I was frustrated that my answer was rejected, but decided not to because my guesswork counts for nothing in the real world. Maybe this problem should be located in the logic section (though that might, unfortunately, give the answer away).
That was highly unexpected.
It says a non-zero amount. You could start with negative infinity.
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you cannot have negative no. of marbles though !!
But, where is ANY hint of "bag within bag" in the question ???
Oh, so each bag is inside the other?
This solution made my day :)
Similar Unique method
Thats what I thought of!
I don't understand this. Could you please explain?
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Sum of numbers inside each ellipse represents the number of marbles in each respective bags.
Whoaa...are you kidding me...too great man, hats off to you....
EXCELLENT!! Unexpected
First I thought 63, then i saw the rating of the problem which was 80points at the time and no problem would be rated that high if it was so simple. So i thought for a while and figured it out.
Hats off Pi Han Goh I thought it was 63
It was indeed a brilliant problem!!
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