sum of integers - 2

The numbers form an arithmetic progression with first term of $11$ and common difference of $11$ . To find for the number of terms we divide $50000$ by $11$ and it is approximately $4545.454545$ , so the number number of terms is $4545$ . To get the last term we multiply $4545$ by $11$ and that is $49995$ . So the sum of the progression is

$s=\dfrac{n}{2}(a_1+a_n)=\dfrac{4545}{2}(11+4995)=\boxed{113638635}$