Sum of Integers

Algebra Level 2

Conan wrote down 10 consecutive positive integers. If the sum of the 5 smallest positive integers is A, then what is the sum of the 5 largest positive integers in terms of A?

A+5 2A 5A A+25

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2 solutions

A/5 is the average that is the middle number. For next five the middle number would be.....> (A/5 + 5) so their sum is 5 * (A/5 + 5) = A + 25.

Nice solution.

Muhammad Mahdi Shahriar Sakib - 6 years, 9 months ago
Evan Lee
Aug 15, 2014

1+2+3+4+5=15 6+7+8+9+10=40… Hence, A+25 is the difference for the next five terms against the first five terms, 40-15=25...

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