Find the sum of all odd integers from 16 to 659 inclusive.
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If you aren't familiar with AP, refer the last of the solution.
Number of terms in an AP = d l − a + 1
In this case, n = 2 6 5 9 − 1 7 + 1 = 3 2 2
Sum of terms of AP = 2 n ( a + l ) Here, sum = 2 3 2 2 ( 1 7 + 6 5 9 ) = 1 0 8 8 3 6
Note:
First term of an AP = a
Last term of an AP = l
Difference between 2 consecutive terms = d
Number of terms in an AP = n