Let a , b , c , d . . . be positive integers.
Is it possible to find such a set of integers such that a + b + c + . . . = 2 0 0 and a 2 + b 2 + c 2 + . . . = 3 0 0 0 0 ?
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Alternatively, 1 7 3 + 7 + 2 + 1 8 × 1 = 2 0 0 and 1 7 3 2 + 7 2 + 2 2 + 1 8 × 1 2 = 3 0 0 0 0 . I wonder how many solutions there are. I initially tried a theoretical approach but didn't really get anywhere - do you have any insights about when the answer to the general problem is "yes" and when it's "no"?
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Third solution: {172, 20, 2, 2, 2, 2}
I don't have any insights about the general problem.
1 7 2 + 2 0 + 2 + 2 + 2 + 2 1 7 2 2 + 2 0 2 + 2 2 + 2 2 + 2 2 + 2 2 = 2 0 0 = 3 0 0 0 0
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1 7 3 + 4 + 4 + 4 + 3 + 2 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 = 2 0 0
1 7 3 2 + 4 2 + 4 2 + 4 2 + 3 2 + 2 2 + 1 2 + 1 2 + 1 2 + 1 2 + 1 2 + 1 2 + 1 2 + 1 2 + 1 2 + 1 2 = 3 0 0 0 0