Sum of the mean, median, and mode

When summing the $\mathbf{{\color{#D61F06} Mean}}$ , $\mathbf{{\color{navy} Median}}$ , and $\mathbf{{\color{#20A900} Mode}}$ : $\\$

$\mathbf{{\color{#D61F06} Mean}}$ (Sum of digits $\div$ number of digits) : $(2+3+0+3+1+4+0+3+2) \ \div \ 9 \ =$ $\mathbf{\boxed{{\color{#D61F06} 2}}}$ $\\$

$\mathbf{{\color{navy} Median}}$ (The middle digit of a set of numbers in ascending/descending order): $0, \ 0, \ 1, \ 2, \ \boxed{2}, \ 3, \ 3, \ 3, \ 4 \ = \mathbf{\boxed{{\color{navy} 2}}}$ $\\$

$\mathbf{{\color{#20A900} Mode}}$ (Most commonly occurring number): $0, \ 0, \ 1, \ 2, \ 2, \ \boxed{3, \ 3, \ 3,} \ 4 \ = \ \mathbf{\boxed{\color{#20A900} 3}}$

$\mathbf{{\color{#D61F06} Mean}}$ $+$ $\mathbf{{\color{navy} Median}}$ $+$ $\mathbf{{\color{#20A900} Mode}}$ $=$ $\mathbf{{\color{#D61F06} 2}}$ $+$ $\mathbf{{\color{navy} 2}}$ $+$ $\mathbf{{\color{#20A900} 3}}$ $=$ $\boxed{7}$

The answer is $\boxed{7}$

Ascending, the numbers would be
0, 0, 1, 2, 2, 3, 3, 3, 4.

n(0) = 2
n(1) = 1
n(2) = 2
n(3) = 3
n(4) = 1

Total frequency
= 2 + 1 + 2 + 3 + 1
= 9

Total sum
= 2(0) + 1(1) + 2(2) + 3(3) + 1(4)
= 0 + 1 + 4 + 9 + 4
= 18

Mode = 3 with highest frequency of 3.

Mean = total sum ÷ total frequency
= 18 / 9 = 2

Median at (9 + 1)/2 = 5th place.
0, 0, 1, 2, { 2 } , 3, 3, 3, 4.
Median = 2

Answer = 3 + 2 + 2 = 7