What is the sum of the red angles inside the polygon in degrees?
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What software did you use in your diagram?
The formula for the sum of all interior angles is S = ( n − 2 ) 1 8 0 ∘ where n = # of sides
Yes, correct.
What?? If I'm not mistaken, the interior angle sum theorem applies if the polygon is convex. For example, I can construct a six-sided polygon with an interior angle sum of 585 degrees.
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Nope, it applies to any polygon and can be proven via induction
I think this problem should be edited.
But, Kano, I have a counterexample. 6 sided figure, 540 degrees, not equal to (6-2)*180. I don't know yet how to attach photos. But believe me, you can do it with 2 90 degree angles, two 45 angles, and two 135 angles.
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https://www.mathsisfun.com/geometry/interior-angles-polygons.html A lot of mathematicans have agreed that this formula is true for any polygon, so therefore it must be true right? Your argument is silly as I could say '6 sided figure, angle sum is 70 degs. With 5 10 degree angles and 1 20 degrees angle
The website you directed to me is all about convex polygons (regular polygons are a subset of convex polygons). So, I'm correct. To disprove something, it just takes one counterexample.
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